Raymond B. answered 03/11/22
Math, microeconomics or criminal justice
60 and 75 mph
Let F = First train's speed
Let S = Second train's speed
The First train traveled for 6 hours
The Second train traveled for 3 hours
distance = speed times time traveled.
the First train traveled a distance of 6F
the Second traveled a distance of 3S
6F -3S = 270
6(S+15) -3S = 270
6S +90 -3S = 270
3S = 270-90 = 180
S = 180/3 = 60 mph
F = 60+15 = 75 mph