Roger N. answered 03/10/22
. BE in Civil Engineering . Senior Structural/Civil Engineer
Solution:
let y = 𝑓(𝑥) = [(x2 − 9) √𝑥 + 2]2 Use chain rule to find f'(x)
y' = f'(x) = 2[(x2 − 9) √𝑥 + 2]2-1( d( (x2 − 9) √𝑥 + 2) /dx) = 2[(x2 − 9) √𝑥 + 2] [ d( (x2 − 9) √𝑥 + 2) /dx]
now expand to d( x2√x -9√x + 2) /dx = d( x2.x1/2 - 9 x1/2 + 2) / dx = d( x5/2 -9 x1/2 + 2) / dx
= (5/2) x(5/2-1) - (1/2)(9)(x)1/2-1 + 0 = (5/2) x3/2 - (1/2)(9)(x)-1/2 = (5/2) x3/2 - (4.5) x-1/2 = (5/2) x √x - 4.5/√x
y' = 2[(x2 − 9) √𝑥 + 2] [ 5/2 x √x - 4.5/√x] = [2√𝑥 (x2 − 9) + 4] [ 5/2 x √x - 4.5/√x ]
you can further expand this answer by using the foil method, but that won't be necessary because you can leave the answer in this form