
Yefim S. answered 03/06/22
Math Tutor with Experience
Let x = x(t) is volume of water in tank at time t. Then rate dx/dt = 8 - √t - 1; dx/dt = 7 - √t;
x(t) = 7t - 2/3t3/2 + C; x(0) = C = 30. x(t) = 7t - 2/3t3/2 + 30
Bethany N.
asked 03/06/22water is pumped into an underground tank at a constant rate of 8 gallons per minute. water leaks out of the tank at the rate of √t+1 gallons per minute, for 0≤t≤120 minutes. At time t=0, the tank contains 30 gallons of water.
Yefim S. answered 03/06/22
Math Tutor with Experience
Let x = x(t) is volume of water in tank at time t. Then rate dx/dt = 8 - √t - 1; dx/dt = 7 - √t;
x(t) = 7t - 2/3t3/2 + C; x(0) = C = 30. x(t) = 7t - 2/3t3/2 + 30
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