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Question

Find three consecutive odd integers such that three times the greatest is 7 les than the sum of the smallest and middle integer.

Answer 1

3L = S + M - 7

3(x+2) = x-2 + x - 7

3x + 6 = 2x -9

x = -15 = the middle odd integer

x+2 = -13 = the larger integer

x-2 = - 17=the smaller integer

the numbers are -17, -15, and -13

3(-13) = -17 -15 - 7

-39 = -39