
Robert J. answered 03/23/13
Tutor
4.6
(13)
Certified High School AP Calculus and Physics Teacher
x+6 = x^2+6 => x = x^2 => x = 0, 1
or
-x-6 = x^2+6 => x^2+x+12 = 0
Since b^2-4ac = 1-4*12 < 0, there is no real solution.
Answer: x = 0, 1
Moriah R.
sorry...left out an x.... | x+6|=x^2+6x
03/23/13