Inactive Tutor answered • 03/23/13
Tutor
New to Wyzant
x+6 = x^2+6 => x = x^2 => x = 0, 1
or
-x-6 = x^2+6 => x^2+x+12 = 0
Since b^2-4ac = 1-4*12 < 0, there is no real solution.
Answer: x = 0, 1
Moriah R.
asked • 03/23/13solve absolute value
|x+6|=x^2+6x solve the equation
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Moriah R.
sorry...left out an x.... | x+6|=x^2+6x
03/23/13