Raymond B. answered 03/02/22
Math, microeconomics or criminal justice
Area = 20x^2 -50x square inches
A = 10x(x-5). Maybe length is 10x and width =x-5
X>5, x is at least 5 inches
x width Length area
6 1 60 60
7 2 70 140
8 3 80 240
9 4 90 360
...
but from the given information, length and width could be anywhere from zero to infinity. something seems missing from the problem.