The perimeter of a rectangle is 1 and its width is 2 times the length whats the length

Answer 1

Let's let L be the length, W the width and P the perimeter. P = 2L + 2W since the opposite sides of a rectangle are equal.

Also, they tell us that the width is twice the length, so W = 2L (weird, since length is usually longer than width).

Substituting for W: P = 2L + 2(2L) -> P = 2L + 4L = 6L

If the perimeter is given as 1, then 1 = 6L and L = 1/6 (after dividing both sides by 6)

To check: The sum of the 4 sides (perimeter) would be 1/6 + 2/6 + 1/6 + 2/6 = 6/6 or 1

Answer 2

So Parker M.,

You solve all such problems the same!

0) We will transform the word problem (difficult to think about or solve in your head) into a math equation (easy to write down, and solve).

1) Assign a variable name to a significant thing in the problem. Since the width is two times the length, assign the variable as the smaller thing, the length of the rectangle. Let's call our variable "Y".

2) So what do we know? If the length is Y, then the width is 2*Y = 2Y for short.

3) Now, put the problem back together. We are given a value for the perimeter. You should know, I hope, by this point, that perimeter means the distance around the edges, just once around.

4) So what is the perimeter length in terms of the edges? It's two widths, plus two lengths, right?

5) So write that as an equation:

P = perimeter length = 2*w + 2*l = 2*(2Y) + 2*(Y) (substituting in the variables we assigned above). = 6Y

6) And, we were told above, that the perimeter length was = 1 . So 1 = 6Y ; Y=(1/6) = the length.

So now, review the strategy above, so that you can apply it yourself, your next problem.

--Cheers, --Mr. d.