Suppose that y varies inversely as the square of x, and that y=9 when x=14. What is y when x=9? Round your answer to two decimal places if necessary.

Answer 1

y=k/x^2

9=k/14^2

k= 9(14)^2 =1764

y=1764/x^2

y = 1764/9^2 = 1764/81

y = 21.777.... = about 21.78

y = 21.78