What is the missing constant term in the perfect square that starts with x^2-12xx 2 −12xx, squared, minus, 12, x ?

Answer 1

x^2 - 12 x + (12/2)^2

= x^2 -12x + 36

= (x-6)^2

to complete the square take half the x term's coefficient and square it. Half of 12 is 6. square it and it's 6^2 = 36