Braxton J.

asked • 02/01/22

one plane is ascending at a rate of 40ft per minute. Another plane is ascending at a rate of 3800ft of 120ft per minute. How long will it take the planes to be at the same altitude

one plane is ascending at a rate of 40ft per minute. Another plane is ascending at a rate of 3800ft of 120ft per minute. How long will it take the planes to be at the same altitude

Mark M.

Garbbled! Review for accuracy.
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02/01/22

Stanton D.

If the second plane is starting at 3800 ft., and the first plane at ground level, they will never coincide. Except perhaps at negative time, underground. That's why we don't let theoretical mathematicians fly planes....
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02/01/22

Mark M.

Waka, waka!
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02/01/22

Barry D.

tutor
I researched and found the actual problem. Here are functions for heights of planes with respect to elapsed time: A(t) = 40t + 520 and D(t) = -120t + 3800 The planes are at same altitude when A(t) = D(t) 40t + 520 = -120t + 3800 160t = 3280 & t = 20.5 min
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02/13/22

Lily G.

tutor
To comment further - Barry's actual functions mean that the altitude of the first plane is rising by 40 ft/minute and starts (time t=0) at 520 ft. The second plan is actually descending, so it is written with a negative slope of -120 ft/second, and is starting at an altitude of 3800. There the first flight starts lower and is rising, while the second plane is starts higher and is dropping. Thus they will, as Barry noted above, be at the same altitude after 20 minutes and 30 seconds.
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03/20/22

1 Expert Answer

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Nathanuel D. answered • 05/19/22

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