note that Fx= 3y2-1 = 2 at (2,1) and Fy=6xy-1 = 11 at (2,1) and F(2,1)= 3. Thus the tangent plane will be 2(x-1)+11(y-1)+3 = L(x,y). Note that L(x,y) is also the linear approximation of F nearby (2,1) thus L(2.1,.9)=2.1.
The DD is the del of F. u where u is a unit vector pointing in the desired direction = .707<1,1>. Thus the DD = 2*.707+11*.707= 13/sqrt(2)