Can someone please help me with this Chemistry question

Question

To determine the heat capacity of a bomb calorimeter, a student added 150g of water at 50 degrees Celsius to the bomb. The bomb initially was at 20 degrees Celsius. The final temperature of the water and the bomb was 32 degrees celsius. What is the heat capacity of the bomb in J/degrees Celsius.

Answer 1

The loss of energy of the water = the gain of energy of the calorimeter:

mc_w( T_i,w - T_f) = C_Cal(T_f - T_i,Cal) You know everything but C_Cal with c_w= 4.184 J/gK

Note that the units of the calorimeter heat capacity is J/K and that Kelvin and Celsius have same spacing.