Write an equation for a line perpendicular to Y= -3x - 1 and passing through the point (6,-2)

Answer 1

y=-3x -1

through the point (6,-2)

is a line with slope = the inverse of -3 = 1/3 = (y+2)/(x-6)

cross multiply to get

x-6 = 3y + 6

3y= x -12

y = x/3 - 4