Can you answer for me?

Question

The length of a rectangle is five less than twice its width. Find the perimeter of this rectangle if its area is 273 yd.²

Answer 1

L=2W-5

A=273 = LW = (2W-5)W = 2W^2 -5W

2W^2 - 5W -273 = 0

W = 5/4 + or - (1/4)sqr(25+4(2)(273)) = (5 + or - 47)/4 = 52/4 or a negative number you can ignore

W = 52/4 = 13 yards

L = 21 yards

21x13 = 273

Perimeter = 2(L+W) = 2(13+21) = 2(34) = 68 yards