Osman A. answered • 11/26/21

Professor of Engineering Mathematics – ACT Math & Science and SAT Math

What is the value of k so that** f(x) = a(x - h)**^{2}** + k **has vertex on the x-axis

__Detailed Solution:__

Given/Known: Vertex: x = h, y = k ==> vertex on the x-axis: **y = k = 0** ==> vertex: **(h, k) = (h, 0)**

f(x) = a(x - h)^{2} + k

f(x) = a(x - h)^{2} + 0

**f(x) = a(x - h)**^{2}