Find 3 consecutive odd integers such that the sum is 7 times the smallest and twice the largest is -73

Answer 1

7S + 2L = -73

S= smallest

M= middle sized number

L= largest

S=x-2

L=x +2

M = x

7(x-2) + 2(x+2) = -73

7x -14 + 2x + 4 = -73

9x = -73 -4+14 = -63

x = -63/9 = -7

x =-7 = the middle odd number

the 3 odd integers are - 9, -7 and -5

7(-9) + 2(-5) = -63 -10= -73