Write an equation for a line with an x intercept of 5 and a y intercept of 8

Answer 1

y = mx + b where b is the y-intercept and m is the slope.

You're given the y-intercept of 8; that also corresponds to the point (0,8)

The x-intercept of 5 means (5,0)

To find slope: m = (y2-y1)/(x2-x1) = (0-8)/(5-0) = -8/5

So you can write an equation as follows: y = (-8/5)*x + 8

Cheers.