Find the length and width of the jewel case.

Question

The length of a standard jewel case is 6 cm more than its width. The area of the rectangular top of the case is 352 cm^2

Answer 1

(6+w)w = 352

6w + w^2 -352 = 0

w = -6/2 + (1/2)sqr(36+4(352)) = -3 + (1/2)38= 16 cm wide, 6+w = 22 cm long

16 x 22 = 352 cm^2