Suppose that X is an element of A. Then, since A is a subset of B we have that X must be an element of the set B too. But this is a contradiction since by assumption X is not an element of B. The proof is complete.
Perla A.
asked 11/15/21Set relations and set operations
Prove using logical equivalences and valid argument forms.
Let U be the Universal set and A,B a subset of U
If A is a subset of B and X is not an element of B, then X is not an element of A
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