Raymond B. answered 11/16/21
Math, microeconomics or criminal justice
let j= jet speed in still air, w = wind speed
distance divided by time = speed
2040/3 = j-w = 680 against the wind
4320/4 = j+w = 1080 with the wind
add to eliminate w get
2j = 1760, divide by 2
j = 880 mph for the jet in still air
w= 1080-880 = 200 mph for the wind speed