Determine the slope and the y-intercept of the line that passes through (10, 2) and is perpendicular to y=−5x+3

Answer 1

general formula for a linear equation is y-k = m(x-h) where m is the slope and (h,k) is a point on the line

line through the point (10,2) with slope 1/5 is

y-2 = (1/5)(x-10) multiply both sides by 5 to eliminate the fraction

5y -10 = x-10 the -10's on both sides cancel leaving

5y = x is as simple as it gets, but rewrite in standard form as

x-5y = 0 as the line perpendicular to the given equation that goes through the given point

the slope of a perpendicular line is the negative inverse. If the given equation has slope = -5 = -5/1, then change the sign and flip the fraction upside down. to get slope = +1/5

check to see if the point (10,2)=(x,y) is on that line

x-5y =0

10-5(2) = 0

10-10 = 0