Determine the slope and the y-intercept of the line that passes through (10, 2) and is perpendicular to y=−5x+3

Answer 1

x = 5y is the perpendicular line through the point (10,2)

10 = 5(2)

5y=x

y = x/5 = (1/5)x where 1/5 is the slope

the given line had slope = -5. take the negative inverse to get the slope of the perpendicular line. -5 = -5/1. flip it upside down and change the sign to get +1/5 = slope of the perpendicular line