What is an equation of a line perpendicular to the line y=1/2x-3 that contains the point (6,4)

Question

What is an equation of a line perpendicular to the line y=1/2x-3 that contains the point (6,4)

Answer 1

m = 1/2

perp m = -2 (-1/m)

y = -2x + b

to find b sub in (6,4)

4 = -2*6 +b

4 = -12 + b

b = 16

y = -2x + 16