When x < -1, x+1 is negative So l x+1 l = -(x+1)
When x > -1, x+1 is positive. So, l x+1 l = x+1
Taking one-sided limits, you will see that they are not the same. Therefore, the given limit does not exist (DNE)
Kozume S.
asked 11/05/21lim x + 1 / | x + 1|
x→-1
When x < -1, x+1 is negative So l x+1 l = -(x+1)
When x > -1, x+1 is positive. So, l x+1 l = x+1
Taking one-sided limits, you will see that they are not the same. Therefore, the given limit does not exist (DNE)
Luis P. answered 11/06/21
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