ALGEBRA MATH 103

Question

a waterfall has a height of 700 feet. a pebble is thrown upward from the top of the falls with an initial velocity of 24 feet per second. the height of the pebble h in feet after t seconds is given by the equation h=16t2+24+700 . how long after the pebble is thrown will it hit the​ ground?

Answer 1

h(t) = 0 = -16t^2 + 24t + 700,

solve for t

divide by -8

2t^2 - 3t - 87.5 = 0

t = 3/4 + or - (1/4)sqr(9 +4(2)(87.5))

= .about 7.41 seconds