Raymond B. answered 05/06/23
Math, microeconomics or criminal justice
999/3=333 are divisible by 3
3,6,9,12,15,...333, 336,339, ...993,996,999
999/7=142 5/7
7,14,21,...,147,154, ...994
999/21=47 12/21, 47 divisible by 3 and 7
333+142= 475
475-47= 428 total divisible by 3 or 7
999-428= 571 not divisible by 3 or 7