If f (1) = 2 and f (n) = f (n-1) + 5 then find the value of f (6)

Answer 1

f(n) = f(n-1) +5

f(6) = f(5) +5

f(1) = f(0) +5 = 2, f(0) = -3

f(2) = f(1) +5 = 2+5 = 7

f(3) = f(2)+5 =7+5= 12

f(4) = f(3)+5 = 12+5 = 17

f(5) = f(4)+5 = 17+5 = 22

f(6) = f(5)+5 = 22+5 = 27