Hello,
Here you just have to remember that the trigonometric functions are all just the ratios of different sides of a triangle. This means that you can use the known values to build up a triangle which can then be used to find the other trigonometric functions.
For example,
If sin(θ) = (√3)/2
and sine = opp/hyp
Then we know that the opposite side of the triangle is √3 units long and the hypotenuse is 2 units long.
From there we can use the Pythagorean theorem to solve for the adjacent side.
a2 + b2 = c2
we know
a = (√3)/2
c = 1
b = adj
[(√3)/2]2 + b2 = 12
Now solve for b
b = √(1 - 3/4)
b = 1/2
Now we know all the sides.
Your question is also telling you that your triangle sits in the 3rd quadrant, meaning both x and y are negative. Let's assume sin(θ) = (√3)/2 is in the 3rd quadrant as well.
To find the other trig functions,
y = opp = -(√3)/2
x = adj = -1/2
hyp = 1
sin(θ) = -(√3)/2
cos(θ) = -1/2
tan(θ) = √3
csc(θ) = -2/√3
sec(θ) = -2
cot(θ) = 1/√3
Let me know if this helped or if you need any further clarification!