Raymond B. answered 01/04/26
Tutor
5
(2)
Math, microeconomics or criminal justice
5, 4 and 3 are the 3 sides, a Pythagorean Triple
(x+2)^2 = x^2 + (x+1)^2
x^2 +4x +4 = x^2 +x^2 +2x +1
x^2 -2x -3 = 0
(x-3)(x+1) = 0
x = 3 or -1
x+1 = 4 or 0
x+2 = 5 or 1
sides are 3,4, and 5, or theoretically also -1, 0 and 1