Raymond B. answered 10/07/21
Math, microeconomics or criminal justice
4 possible solutions
try some simple integers such as x=1
2x^4 -11x^3 + 12x^2 +x -4
2 -11 +12 +1 - 4 = 0
x=1, a factor is x-1. Divide the quadratic by x-1 to get
2x^3 -9x^2 +3x +4
try x=1 again, another factor repeats, x-1
divide x-1 into the cubic
to get
2x^2 -7x -4
(2x+1)(x-4) = 0
x=-1/2, 4
4 real solutions although 1 solution repeats
(x-1)^2(2x+1)(x-4) = 0
(x-1)(x-1)(2x+1)(x-4) = 0
set each factor equal to zero
x=1, 1, -1/2, 4