I think i understand what its asking but not 100% sure

Question

Solve the equation. Check all proposed solutions. Show work in solving and in checking and state your final conclusion.

x-3 - 20 =0

x+1 x^2-3x-4

Answer 1

(x-3)/(x+1) - 20/(x^2 -3x -4) = 0

(x-3)/(x+1) -20/(x-4)(x+1) = 0

(x-3)(x-4)/(x+1)(x-4) - 20/(x-4)(x+1) = 0

(x^2 -7x +12 -20)/(x-4)(x+1) = 0

(x^2 - 7x - 8)/(x-4)(x-1) = 0

(x-8)(x+1)/(x-4)(x+1) = 0

(x-8)/(x-4) = 0

x-8 = 0

x = 8

(8-3)/(8+1) - 20/(8^2 -3(8)-4) = 0

5/9 -20/(36) = 0

5/9 - 5/9 = 0