find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less than four times the smaller number

Answer 1

L +2S +27 = 4S

S+2 + 2S +27 =4S

S =29 = the smaller integer

L=31= the larger consecutive odd integer

check the solution:

31+2(29) +27 = 4(29)

116 = 116