USING THE METHOD OF CYLINDRICAL SHELLS
V= 2π ∫025/2 x [ 5 - √(2x) ] d x = 625π/ 4 cubic units
USING THE WASHER METHOD
V = ∫05 π (1/4) y4 d y = 625π/ 4 cubic units
Alya A.
asked 09/26/21USING THE METHOD OF CYLINDRICAL SHELLS
V= 2π ∫025/2 x [ 5 - √(2x) ] d x = 625π/ 4 cubic units
USING THE WASHER METHOD
V = ∫05 π (1/4) y4 d y = 625π/ 4 cubic units
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