
Dayv O. answered 09/10/21
Caring Super Enthusiastic Knowledgeable Calculus Tutor
If the solution sought is x(t) then you are right, t is independent and x dependent.
dx/dt = k(4-x)(1-x)
same as x'-k(4-x)(1-x)-0,,,,,first order derivative (isolated so linear), but dependent variable is squared so non-linear. If there are just two variables the equation is ordinary differential equation.
by way, isn't this seperable and solution is (1/3)ln(4-x)-(1/3)ln(1-x)=kt+C
and in a way I could say t(x)=(1/k)*[(1/3)ln((4-x)/(1-x))-C is solution and t is dependent and x independent.
And if the equation is written dt/dx-(1/k)*1/[(4-x)*(1-x)]=0, then it would be first order linear since neither t' or t is in non-linear form.