The length of a rectangle is 7yd more than twice the width x. The area is 855 yd^2

Question

Write an equation in terms of x that represents the given relationship.

Answer 1

L=7+W

A=LW = 855

855 = (7+W)W = 7W +W^2

W^2 +7W -855 = 0

W = -7/2 + or - (1/2)sqr(49+4(855)) =about -3.5 + or - .5(58.9 = about 25.945 yards wide

L = about 32.945 yards

Width = a little less than 26 yards

Length = a little less than 33 yards

If you want it in terms of x

x^2 +7x -855 = 0 where x = width in yards

26x33 =