Raymond B. answered 09/05/21
Tutor
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Math, microeconomics or criminal justice
402/3 = 134
133 + 134 + 135 = 402
x-1 + x + x+1 = 402
3x = 402
x =402/3 = 134 = the middle integer
the 3 consecutive integers are 133, 134 and 135