Inactive Tutor answered 09/05/21
Tutor
New to Wyzant
402/3 = 134
133 + 134 + 135 = 402
x-1 + x + x+1 = 402
3x = 402
x =402/3 = 134 = the middle integer
the 3 consecutive integers are 133, 134 and 135
Sherly C.
asked 09/03/21The sum of three consecutive integers is 402. What are the integers? Enter each number, separated by a comma.
Inactive Tutor answered 09/05/21
402/3 = 134
133 + 134 + 135 = 402
x-1 + x + x+1 = 402
3x = 402
x =402/3 = 134 = the middle integer
the 3 consecutive integers are 133, 134 and 135
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.