Inactive Tutor answered 08/26/21
x+y = 12
y= 3x + 4
x+ 3x+4 = 12
4x = 8
x = 2
y =10
r=n
c=0.5n + 450
if r=c, then
n=0.5n +450
subtract 0.5n from both sides to get
0.5n =450
multiply both sides by 2
n = 900
r=900
c=900
r=c=n=900
Daniel M.
asked 08/26/21I thought I understood substitution to require two like terms in each equation, as in the following:
x+y=12
y=3x+4
How then does the following substitution work as taken from the answer section of my grade 10 math course when R and C are not present in both equations?
r=n
c=0.5n+450
let r =c (*this is what I don't understand - I was taught thus far that for r to equal c it would require that c were present in the first equation).
2n=0.5n+450...I understand the rest pretty much.
Thanks!
Inactive Tutor answered 08/26/21
x+y = 12
y= 3x + 4
x+ 3x+4 = 12
4x = 8
x = 2
y =10
r=n
c=0.5n + 450
if r=c, then
n=0.5n +450
subtract 0.5n from both sides to get
0.5n =450
multiply both sides by 2
n = 900
r=900
c=900
r=c=n=900
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