
Mark M. answered 08/24/21
Mathematics Teacher - NCLB Highly Qualified
f(2) = 2
f(x) - f(2) = [(x + 8) / (x + 3)] - 2
f(x) - f(2) = [(x + 8) - 2(x + 3)] / (x + 3)
f(x) - f(2) = [(-x + 2) / (x + 3)]
[f(x) - f(2)] / (x + 2) = [(-x + 2) / (x + 3)(x - 2)]
[f(x) - f(2)] / (x - 2) = [-(x - 2) / (x + 3)(x - 2)]
[f(x) - f(2)] / (x - 2) = -1 / (x + 3)
Bradford T.
The question is confusing. The definition of the difference quotient for calculus is (f(x+h)-f(x))/h.08/24/21