Take a look at the velocity function
r'(t)= < 15 sec5t tan5t +3t2 , −20 csc5t cot 5t +2 t , −15 csc2t + 4t3 >
The calculations are getting out of hand.
Here you need a calculator with CAS , or better do it on Mathematica.
M P.
asked 08/23/214. (a) Given that, the displacement vector of a particle is r(t) = (3 sec (5t) + t³)i + (4 csc(5t) + t²)j + (5 cot 3t+t4)k, at time t = 0.5 find the magnitude of displacement, speed and the magnitude of acceleration.
(b) Find the curl of V
V = sin(x) cos(y) tan(z)i + x²y²z²j + x4y4z4 k and evaluate its magnitude at x = 0.5, y = 0.7 and z = 0.8.
Take a look at the velocity function
r'(t)= < 15 sec5t tan5t +3t2 , −20 csc5t cot 5t +2 t , −15 csc2t + 4t3 >
The calculations are getting out of hand.
Here you need a calculator with CAS , or better do it on Mathematica.
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