The North Bend Women's Soccer League has eight teams. If each team plays all the others twice, how many games will have been played?

Answer 1

each team plays (8-1)2 = 14 games x 8 teams = 112 games

but that's double counting, so divide by 2 = 56 games total

Team 1 plays 7 other teams twice for 14 games for each team. 8x14 = 112 games total

Team 1 plays 14 games total

team 2 plays 12 games, not counting the 2 games with team 1, as they would be double counting

team 3 plays 10 games,

team 4 plays 8

5 plays 6

6 plays 4

7 plays 2

8's games are already counted in the above

add up 14+12+10+8+6+4+2 = 56 games