USING THE SHELL METHOD
V = 2π ∫04 [ 5−x ] √x d x = (416π) / 15
USING THE DISC METHOD
V = π ∫02 [ (5−y2 )2 − 12 ] d y = (416π) / 15
USING THE SHELL METHOD
V = 2π ∫04 [ 5−x ] √x d x = (416π) / 15
USING THE DISC METHOD
V = π ∫02 [ (5−y2 )2 − 12 ] d y = (416π) / 15
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