y = 2√x
Then y1 = 2√4 =4 and y2 = 2√4.4 = 4.195235 . Hence Δy = y2 - y1 = .195235
Now dy / dx = 1 / √x ⇒ d y = d x / √x
Hence d y = 0.4 /√4 ⇒ d y = 0.2
Em K.
asked 07/30/21Let y=2√x.
Find the change in y, Δy when x=4 and Δx=0.4 4.0
Find the differential dy when x=4 and dx=0.4
y = 2√x
Then y1 = 2√4 =4 and y2 = 2√4.4 = 4.195235 . Hence Δy = y2 - y1 = .195235
Now dy / dx = 1 / √x ⇒ d y = d x / √x
Hence d y = 0.4 /√4 ⇒ d y = 0.2
Baluch F. answered 07/30/21
Mathematics is my passion.
Alright, let us tackle it;
First, we rewrite;
y=2x1/2 (In derivation, we use exponents and not root.)
Now the change;
change in y = y(x + change in x) - y(x)
=2(x + change in x)1/2 - 2(x)1/2
=2(4 + 0.4)1/2 - 2(4)1/2
=0.1952
Solving the differential at the given point we first find the derivative...
dy=x-1/2dx;
x = 4 ; dx = 0.4
dy=(4)-1/2(0.4)
=0.4/√4 OR 2/(5√4) OR 1/5 OR 0.2.
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Em K.
This is not right as differential has 0.2 answer not the change.07/30/21