Tom N. answered 07/26/21
Strong proficiency in elementary and advanced mathematics
Using the trig substitution x= 10 tanθ and dx = 10 sec2θ in the original integral along with the identity 1+tan2θ =sec2θ it becomes (-16/100)∫sec2θ/tan2θsecθ. This simplifies to (-16/100)∫secθdθ/tan2θ which can be written as (-16/100)∫cos2θdθ/cosθsin2θ which now becomes(-16/100)∫cosθdθ/sin2θ. (1) Using a u substitution for sinθ where du becomes cosθdθ the integral becomes (-16/100)∫du/u2 and hence the integral becomes (4/25)cscθ + C. (2) Substituting back to x gives (4/25) ((x2 +100)1/2/x) + C as the answer.