
Patrick B. answered 07/25/21
Math and computer tutor/teacher
it is Clairuat's 1st order non-linear
y = x y' + 1/(y')^2 = xy' + f( y') where f(t) = 1/t^2
the general solution is y = cx + f(c)
the singular envelopes are x = -f'(c) and y = f(c) - c f'(c)
mathworld DOT wolfram DOT com / ClairautsDifferentialEquation DOT html

Patrick B.
well no, because then the posting gets flagged; stay in your lane...07/25/21