Sob R.
asked • 07/23/21find the indefinite integral
∫x2-3x-7/(2x+3)(x+1)dx
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1 Expert Answer
Let assume that you mean
∫(x2-3x-7)/(2x+3)(x+1)dx
After performing the long division and partial fraction decomposition we get
∫(x2-3x-7)/(2x+3)(x+1)dx = ∫[ 1/2 + 11/(x+1) - (55/2)(1/(2x+3) ] d x
= (1/2)x + 11ln | x+1| - (55/4) ln| 2x +3| +λ, where λ is constant
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Paul M.
07/23/21