2r dr/ds + 2√t = t dr/ds
dr/ds = -2t/(2r-t)
True, by the Chain Rule
Leibnitz notation for the chain rule : dy/dx = dy/du * du/dx which is easy to remember
or f'(x) = f'(u(x)) * u'(x)
In this case u(x)=√x.
Nithin D.
asked 07/22/21Hey, Need some help with two homework problems, thanks!
Find dr/ds where t is a constant. Show all work. r2+2s sqrt(t) = r*t
Determine if the statement is true or false.
If f is differentiable, then d/dx f(sqrt(x)) = f'(x)/(2 * sqrt(x))
2r dr/ds + 2√t = t dr/ds
dr/ds = -2t/(2r-t)
True, by the Chain Rule
Leibnitz notation for the chain rule : dy/dx = dy/du * du/dx which is easy to remember
or f'(x) = f'(u(x)) * u'(x)
In this case u(x)=√x.
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Nithin D.
Do you mind elaborating a little bit more on the second question? I have to write a couple sentences about it. Thanks!07/22/21