M P.
asked • 07/16/21Solve the differential equation
solve the differential equation x^2y+xy'+zy=0
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1 Expert Answer
Obviously solve the equation x2y + x y' +2y = 0
x2 y dx + x dy + 2y dx = 0
x dy + y( x2 + 2) dx = 0
(d y ) /y = - [(x2 +2 )/ x] dx separable..........
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Paul M.
07/16/21