Raymond B. answered 07/15/21
Math, microeconomics or criminal justice
R=100x -.5x^2
C = 60x + 300
Profit = R-C = -5x^2 +40x -300
Max profit is when R'-C'= 0 = 40-x, x=40
Max profit = -.5(40)^2 +40(40 -300 = 1600 -300- 800 = $500
part c) No, it's not possible to make a profit of $2500. At least not with the given information. But revenue and cost are for some specific time period not given in the problem. $500 is the maximum possible for some unspecified time period. Over 5 times as long, and $2500 is possible.
part b) for x=30, profit = 450
for x=20 profit = 300
for x =10 profit= $50
for x = 70 profit = 2800-300-2450= $50
set R-C = 50 = -.5x^2 +40x -300
-.5x^2 + 40x -350 =0 multiply by -2
x^2 -80x +700 = 0 factor (or if you don't see the factors, complete the square or use the quadratic formula)
(x-70)(x-10) =0
x=10 or 70