
Yefim S. answered 07/08/21
Math Tutor with Experience
Let x is distance from projecton of light to the projection of lamp onto the wall. Then x = 19tanθ;
dx/dt = 19sec2θdθ/dt; θ = 20° and dθ/dt = 2π/5 sec-1.
So, dx/dt = 19sec220°·2π/5 ft/sec = 27.04 ft/sec