(2B.19) What is the rule for the nth term, an, when the first 4 terms of the sequence are 4, 16, 64, 256? A. an=(‒4)n‒ 1 B. an=4n C. an=4n‒ 1 D. an=4n

Answer 1

an= 4(4)^(n-1) = 4^n

an=4^n

an =a1(r^n-1) r= the common ratio = 4, a1 =4

an =4(4^n-1) = 4^n

a1 = 4(4)^0 = 4^1= 4

a2 = 4(4^1) =4^2 = 16

a3 = 4(4^2) = 4^3 = 64

a4 = 4(4^3) = 4^4 = 256